English
CollectionUtils
About 269 wordsLess than 1 minute
2026-01-09
Methods for handling collections
- CollectionUtils.union(list1,list2): Returns the union of two lists
Example:
def list1 = ["A", "B", "C", "D", "E", "F"]
def list2 = ["B", "D", "F", "G", "H", "K"]
def re = CollectionUtils.union(list1, list2)
log.info(re) // [A, B, C, D, E, F, G, H, K]- CollectionUtils.intersection(list1,list2): Returns the intersection of two lists
Example:
def list1 = ["A", "B", "C", "D", "E", "F"]
def list2 = ["B", "D", "F", "G", "H", "K"]
def re = CollectionUtils.intersection(list1, list2)
log.info(re) //[B, D, F]- CollectionUtils.disjunction(list1,list2): Returns the complement of the intersection of two lists (disjunction)
Example:
def list1 = ["A", "B", "C", "D", "E", "F"]
def list2 = ["B", "D", "F", "G", "H", "K"]
def re = CollectionUtils.disjunction(list1, list2)
log.info(re) //[A, C, E, G, H, K]- CollectionUtils.subtract(list1,list2): Returns the difference between two lists (subtraction)
Example:
def list1 = ["A", "B", "C", "D", "E", "F"]
def list2 = ["B", "D", "F", "G", "H", "K"]
def re = CollectionUtils.subtract(list1, list2)
log.info(re) //[A, C, E]- CollectionUtils.isEqualCollection(list1,list2): Determines whether two collections are equal
Example:
def list1 = ["A", "B", "C", "D", "E", "F"]
def list2 = ["A", "F", "B", "C", "D", "E"]
def re = CollectionUtils.isEqualCollection(list1, list2)
log.info(re) //true- CollectionUtils.isSubCollection(list1,list2): Determines whether list1 is a subset of list2
Example:
def list1 = ["A", "F"]
def list2 = ["A", "B", "C", "D", "E", "F"]
def re = CollectionUtils.isSubCollection(list1, list2)
log.info(re) //true- CollectionUtils.cardinality(str,list1): Returns the number of occurrences of an element
Example:
def list1 = ["A", "A", "A", "D", "E", "F"]
String str = "A"
def re = CollectionUtils.cardinality(str, list1)
log.info(re) //3